if x =a sec and y =b tan theta, then b²x²-a²y ²
with full method
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Answer: The answer is a²b².
Step-by-step explanation:
x = a sec(theta) and y= b tan(theta)
b²x²-a²y² = b²a²sec²(theta) - a²b²tan²(theta)
= a²b²{sec²(theta) - tan²(theta)}
= a²b² × 1 = a²b²
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