Question

if x=a sec theta
and y = a tan theta then x^2-y^2=

A) 1
B) a
c) a²
d) o​

Answer 1

assume theta =b

x=a secb,y=a tanb

x²-y²=a²sec²b-a²tan²b

=a²(sec²b-tan²b)

=a²(1)=a²