Question

If X = a sec∅ , y = a tan∅ find the value of x²-y²

Answer 1

HEY MATE YOUR ANSWER IS HERE

WE HAVE X² - Y² = ( a sec∅)² - ( a tan∅)²

= a² ( sec²∅ - tan²∅ )

= a² × 1

= a²

Thanks for the question hope it helps

Answer 2

★ Answer :

X = a sec∅ ........(1)

y = a tan∅ ..........(2)

As, we have to find the value of x² - y². Then, we get

→ x² - y² = (a sec∅)² - (a tan∅)²

→ x² - y² = a² Sec²∅ - a² tan²∅

→ x² - y² = a²(Sec²∅ - tan²∅)

We know that,

Sec²∅ - tan²∅ = 1

→ x² - y² = a²(1)

→ x² - y² = a²