Question

If x = a secA and y = a tanA , then the value of x2 - y2 is

Answer 1

Answer:

x²-y²= a

Step-by-step explanation:

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Answer 2

Answer:

Given, x = a sec A & y = a tan A

Squaring these, then we get,

x² = a² sec²A & y² = a² tan² A

x²/a² = sec²A & y²/a² = tan²A

Subtract these, so we get,

x²/a² - y²/ a² = sec²A - tan²A

x² - y² /a² = 1 [°.° sec²A - tan²A = 1]

x² - y² = a²

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