If x = a sin 0, y = b cos o then prove that x^2/a^2 + y^2/b^2 =1
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Answer:
xcosθ−ysinθ=a......(1)
xsinθ+ycosθ=b.....(2)
(1)
2
+(2)
2
(xcosθ−ysinθ)
2
+(xsinθ+ycosθ)
2
=a
2
+b
2
x
2
cos
2
θ+y
2
sin2θ−2xysinθcosθ+x
2
sin
2
θ+y
2
cos
2
θ+2xycosθsinθ=a
2
+b
2
x
2
(cos
2
θ+sin
2
θ)+y
2
(sin
2
θ+cos
2
θ)=a
2
+b
2
x
2
+y
2
=a
2
+b
2
Step-by-step explanation:
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