Question

if x=a sin theta and y=a cos theta ,then find the value of x square + y square

Answer 1

x=a sin theta
y=a cos theta
therefore, x^2+y^2= a*a*sin*theta+a*a*cos theta
=a*a(sin*theta+cos*theta)
=a*a(1)
=a*a or a^2

Answer 2

Answer:

The answer is a².

Step-by-step explanation:

Given,

$x=a sin \theta$ -------(1)

$y=a cos \theta$ -------(2),

( Equation (1) )² + ( Equation (2) )²

$\implies x^2 + y^2 = (a sin \theta)^2 + (a cos \theta)^2$

$= a^2 sin^2 \theta + a^2 cos^2 \theta$

$= a^2 ( sin^2 \theta + cos^2 \theta)$

$= a^2$ ( Because, sin² A + cos² A = 1 )