Question

If x=a sin theta and y=b cos theta, what is the value of b^2x^2+a^2y^2

Answer 1

Answer: Here is the easy answer dude.

Step-by-step explanation: x = a sin theta

y = b cos theta

b2x2 + a2y2

= b2a2sin2 theta + a2b2cos2 theta

= b2a2 (cos 2 theta + sin 2 theta)

= b2a2 × 1

= a2b2