If x=a sin theta and y=b cos theta, what is the value of b^2x^2+a^2y^2
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Answer: Here is the easy answer dude.
Step-by-step explanation: x = a sin theta
y = b cos theta
b2x2 + a2y2
= b2a2sin2 theta + a2b2cos2 theta
= b2a2 (cos 2 theta + sin 2 theta)
= b2a2 × 1
= a2b2
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