If x=a sin theta and y=b tan theta prove that a²/x²-b²/y²=1
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Answered by
6
hey friend here is your answer
putting value if x&y in equation
we find,a2/a2sin2t-b2/tan2t
=changing in sin
a2/a2sun2t-b2cos2t/b2sin2t
taking LCM
=a2b2-a2b2cos2t/a2b2sin2t
taking common a2b2
we find
a2b2(1-cos2t)/a2b2sin2t
using formula
a2b2sin2t/a2b2sin2t
=1
Hence proved
putting value if x&y in equation
we find,a2/a2sin2t-b2/tan2t
=changing in sin
a2/a2sun2t-b2cos2t/b2sin2t
taking LCM
=a2b2-a2b2cos2t/a2b2sin2t
taking common a2b2
we find
a2b2(1-cos2t)/a2b2sin2t
using formula
a2b2sin2t/a2b2sin2t
=1
Hence proved
Answered by
5
# Hope this will help you
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sureshnilesh000:
Thanx this helped me a lot
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