Question

If x = a sin theta and y = bcos theta ,   determine the value of b2x2+a2y2

Answer 1

x = a sin theta
y = b cos theta

b2x2 + a2y2
= b2a2sin2 theta + a2b2cos2 theta
= b2a2 (cos2 theta + sin2 theta)
= b2a2 × 1
= a2b2

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Answer 2

Answer:

b^2 × x^2 + a^2 × y^2

=b^2 × a sin^2theta + a^2 × b^2 cos^2theta

=b^2 × a^2 × (cos^2theta + sin^2theta)

=b^2 × a^2 × 1

=a^2 × b^2

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