if x = a sin theta + b cos theta and y = a cos theta minus B sin theta then find the value of x square + Y square
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X = a sinΘ + b cosΘ
Y = a cosΘ - b sinΘ
X² + Y² = (a sinΘ + b cosΘ)² + (a cosΘ - b sinΘ)²
= a²sin²Θ + b²cos²Θ + 2ab sinΘ cosΘ + a²cos²Θ + b²sin²Θ - 2ab sinΘ cosΘ
= sin²Θ(a² + b²) + cos²Θ(a² + b²)
= (sin²Θ + cos²Θ) ( a² + b²)
= a² + b²
Answer is a² + b²
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