Question

if x=a sin theta, y=a cos theta then find value of x sq+y sq​

Answer 1

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Answer 2

Given,

$x = a \sin \theta$

$y = a \sin \theta$

Therefore,

${x}^{2} + {y}^{2} = (a \sin \theta)^{2} + {(a \cos \theta)}^{2}$

$= {a}^{2} \sin^{2} \theta + {a}^{2} { \cos }^{2} \theta$

$= {a}^{2} (\sin^{2} \theta + { \cos }^{2} \theta)$

$= {a}^{2}×1$

$= {a}^{2}$

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