if x = a sintheta and y = b costheta then b^2x ^2 + a^2y^2 is equal to
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Your answer is
Step-by-step explanation:
x=b^4
y=4a
x=b×^4
y=2×2×a
Answered by
0
Answer:
here,
X=asintheta
y= bcostheta
then,
b^2x^2+a^2y^2
putting the value of X and y, we get
=b^2(asintheta)^2 +a^2(bcostheta)^2
=b^2a^2sin^2theta + a^2b^2cos^2theta
taking common a^2b^2,then
=a^2b^2(sin^2theta+ cos^2theta)
we know that: sin^2theta +cos^2theta=1 so,
= a^2b^2
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