Question

if x= a.sinZ and y= b.cosZ, then find the value of b²x² + a²y²​

Answer 1

Answer:

$b^2x^2 + a^2y^2$ $=a^2b^2$

Step-by-step explanation:

Given that, x = a.sinZ and y = b.conZ

$b^2x^2 + a^2y^2$

$=b^2a^2sin^2Z + a^2b^2cos^2Z$

$=a^2b^2(sin^2Z + cos^2Z)$

$=a^2b^2$  [∵ $sin^2x + cos^2x = 1$]