If x = a tan 0 and y = b sec 0, then y2 /b2 - x2/A2=
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Answer:⤵️
1
Step-by-step explanation:⤵️
x=a tan(o)
=> x/a = tan(o) .....(1)
y = b sec (o)
=> y/b = sec(0) ......(2)
then,
y^2/b^2 - x^2/a^2
= sec^2(o) - tan^2(o)
=1
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