Math, asked by harpreet2223, 9 months ago

If x-a whole square+y-b whole square​

Answers

Answered by Anonymous
23

⠀⠀⠀⠀{ \huge {\mathtt{ \green{QUESTION}}}} </p><p>

If x-a whole square+y-b whole square

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⠀⠀⠀⠀⠀\huge{ \purple{ \bold{ \bf{AnSweR }}}}

\bf   : \implies {x}^{2}   +  {y}^{2} +  {a}^{2} +  {b}^{2}  - 2(xa + yb)

⠀⠀⠀⠀⠀\huge\underline{ \underline{ \orange{ \bold{solution}}}}

\bf \: (x - a) {}^{2} + (y - b) {}^{2}   \\  \\  \bf   : \implies \: by\:using\\\\ \bf   : \implies\underline{\boxed  {\bf{\: (a  -  b) {}^{2} = a {}^{2} + b {}^{2}   - 2ab }}}\\  \\  \bf   : \implies \:  {x}^{2} + a {}^{2}   - 2xa + y {}^{2} + b {}^{2}    - 2yb \\  \\\bf   : \implies \:  {x}^{2}  +  {y}^{2}   +  {a}^{2} +  {b}^{2}  - 2xa - 2yb \\ \\ \bf   : \implies {x}^{2}   +  {y}^{2} +  {a}^{2} +  {b}^{2}  - 2(xa + yb)

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Answered by SweetPoison7
0

⠀⠀⠀⠀{ \huge {\mathtt{ \green{QUESTION}}}}QUESTION

If x-a whole square+y-b whole square

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⠀⠀⠀⠀⠀\huge{ \purple{ \bold{ \bf{AnSweR }}}}AnSweR

\bf : \implies {x}^{2} + {y}^{2} + {a}^{2} + {b}^{2} - 2(xa + yb):⟹x

2

+y

2

+a

2

+b

2

−2(xa+yb)

⠀⠀⠀⠀⠀\huge\underline{ \underline{ \orange{ \bold{solution}}}}

solution

\begin{gathered}\bf \: (x - a) {}^{2} + (y - b) {}^{2} \\ \\ \bf : \implies \: by\:using\\\\ \bf : \implies\underline{\boxed {\bf{\: (a - b) {}^{2} = a {}^{2} + b {}^{2} - 2ab }}}\\ \\ \bf : \implies \: {x}^{2} + a {}^{2} - 2xa + y {}^{2} + b {}^{2} - 2yb \\ \\\bf : \implies \: {x}^{2} + {y}^{2} + {a}^{2} + {b}^{2} - 2xa - 2yb \\ \\ \bf : \implies {x}^{2} + {y}^{2} + {a}^{2} + {b}^{2} - 2(xa + yb)\end{gathered}

(x−a)

2

+(y−b)

2

:⟹byusing

:⟹

(a−b)

2

=a

2

+b

2

−2ab

:⟹x

2

+a

2

−2xa+y

2

+b

2

−2yb

:⟹x

2

+y

2

+a

2

+b

2

−2xa−2yb

:⟹x

2

+y

2

+a

2

+b

2

−2(xa+yb)

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Thanks

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