Math, asked by Ashwin9256, 10 months ago

If (x+a)(x+b)(x+c)=x^3-10x^2+45x-15 find a+b+c,1/a+1/b+1/c and

Answers

Answered by rohitrs0908
2

Answer:

Step-by-step explanation:

(x + a)(x + b)(x + c) = x3 + (a + b + c)x2 + (ab + bc + ca)x + abc

Comparing this with

x3 – 10x2 + 45x – 15 = x3 + (a + b + c)x2 + (ab + bc + ca)x + abc

⇒ – 10 = a + b + c  (Co-efficient of x²)

Now,  1/a+1/b+1/c = (bc+ab+ca)/abc

= 45/(-15) = -3  (Co-efficient of x/ Co efficient of constant term)

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