if (x+a)(x+b)(x+c)=x^3-10x^2+45x-15 find a+b+c
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This question having cubic equation on RHS and product of 3 factors in the LHS shows that the cubic equation has three zeroes as -a ,-b, -c.
And, we know sum of zeroes =. -(coefficient of x^2)/(coefficient of x^3)
i.e. -a+(-b)+(-c) = -(-10)/1
-(a+b+c) =10
So, a+b+c= -10.
And, we know sum of zeroes =. -(coefficient of x^2)/(coefficient of x^3)
i.e. -a+(-b)+(-c) = -(-10)/1
-(a+b+c) =10
So, a+b+c= -10.
sas8:
how to find 1/a+1/b+1/c and a^2+b^2 +c^2
Hey, you know the value of a+b+c , abc and ab+bc+ac .
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Hi guys !!!
I have attached the answer below.
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