Question

if(x+a)(x+b(x+c)=x3-3x2-10x+24 find the value of ab+bc+ca , 1/a+1/b+1/c ,a²+b²+c² ,a/bc +b/ac + c/ab​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

a,b,c are roots of equation x^3 -3x^2 +2x +1=0

As we know if three values are the root of a cubic polynomial then,

Ax^3 + Bx^2 + Cx + D=0

Then roots a,b,c

(a+b+c)=-B/A

(ab+bc+ca)=C/A

abc=-D/A

Now coming to the question,

1/a + 1/b + 1/c = (ab + bc + ca)/abc

[2/1]/[-1/1]

-2/1 = -2.