Question

If (x + a)(x+b) = x2 – 5x – 300, find the values of a^2 + b^2.​

Answer 1

Answer:

x

2

−5x−300=x

2

−20x+15x−300=x(x−20)+15(x−20)=(x−20)(x+15)

Given (x+a)(x+b)=x

2

−5x−300

Then (x+a)(x+b)=(x−20)(x+15)

So, compare this we get a=−20 and b=15

Then a

2

+b

2

=(−20)

2

+(15)

2

=400+225=625

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