if(x-a)(x+b)=x2+kx-ab then k is
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Answered by
0
Answer:
(x-a)(x+b)=x^2+kx-ab
=> x(x+b) -a(x+b)= x^2+kx-ab
=>x^2+bx-ax-ab= x^2+kx-ab
=> x^2+(b-a)x-ab=x^2+kx-ab
comparing on both side
k = (b - a)
Answered by
0
Answer:
K=(-a+b)
Step-by-step explanation:
(x-a)(x+b)=x2+kx-ab
x²-ax +bx-ab=x2+kx-ab
x²+(-a+b)x-ab=x2+kx-ab
K=(-a+b)
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