If x/a = y/b = z/c, prove that (x²+a²)/(x+a) + (y²+b²)/y+b + (z²+c²)/z+c = (x+y+z)²+(a+b+c)²/x+y+z+a+b+c.
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Answer:
If x/a = y/b = z/c, prove that (x²+a²)/(x+a) + (y²+b²)/y+b + (z²+c²)/z+c = (x+y+z)²+(a+b+c)²/x+y+z+a+b+c.
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