Question

if x/a=y/b=z/c, prove that x³/a²+y³/b²+z³/c²=(x+y+z)³/(a+b+c)²​

Answer 1

Answer:

Let  x/a = y/b = z/c = k, 

x  = ak,  y = bk  and  z = ck

L.H.S.  = a3k3/a2 + b3k3/b2 + c3k3/c2  k3[a + b + c]

R.H.S. = [ak + bk + ck]3/[a + b + c]2 

  k3[a + b + c]3/[a + b + c]2  

= k3(a + b + c)

L.H.S.  =  R.H.S.

Hence proved.

Hope it helps you.....

Answer 2

Answer:

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