Question

If x/a=y/b=z/c prove that x3/a3 - y3/b3 + z3/c3 = xyz/abc

Answer 1

let x/a=y/b=z/c be = k 
...hence, x=ak, y=bk,z=ck.... 
. 
. 
now put these values in the formulae to be proved. 

LHS will be, 
(a³k³/a³)-(b³k³/a³)+(c³k³/c³) 
=k³-k³+k³ 
=k³ 
. 
. 
RHS will be, 
ak*bk*ck/abc 
=k*k*k 
=k³ 

HENCE PROVED, 
LHS=RHS....:)

Hope it helps!!

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