if, x:a = y:b = z:c
then prove it,
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Answered by
2
Answer:
Let x/a = y/b = z/c = k, [By k method]
x = ak, y = bk and z = ck
L.H.S. = a3k3/a2 + b3k3/b2 + c3k3/c2 ⇒ k3[a + b + c]
R.H.S. = [ak + bk + ck]3/[a + b + c]2 ⇒ k3[a + b + c]3/[a + b + c]2
= k3(a + b + c)
L.H.S. = R.H.S.
Hence proved.
Answered by
1
Answer:
Let x/a = y/b = z/c = k, [By k method]
x = ak, y= bk and z=ck
L.H.S. = a3k3/a2 + b3k3/b2 + c3k3/c2 > k3[a + b + c]
R.H.S. = [ak + bk + ck]3/[a + b + c)2 → k3[a + b + c]3/[a + b + c)2
= k3(a + b + c)
L.H.S. = R.H.S. =
Hence proved.
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