Question

if, x:a = y:b = z:c
then prove it,

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Answer 1

Answer:

Let x/a = y/b = z/c = k, [By k method]

x = ak, y = bk and z = ck

L.H.S. = a3k3/a2 + b3k3/b2 + c3k3/c2 ⇒ k3[a + b + c]

R.H.S. = [ak + bk + ck]3/[a + b + c]2 ⇒ k3[a + b + c]3/[a + b + c]2

= k3(a + b + c)

L.H.S. = R.H.S.

Hence proved.

Answer 2

Answer:

Let x/a = y/b = z/c = k, [By k method]

x = ak, y= bk and z=ck

L.H.S. = a3k3/a2 + b3k3/b2 + c3k3/c2 > k3[a + b + c]

R.H.S. = [ak + bk + ck]3/[a + b + c)2 → k3[a + b + c]3/[a + b + c)2

= k3(a + b + c)

L.H.S. = R.H.S. =

Hence proved.

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