If x^a= y
y^b=z
z^c= x
Prove that abc=1
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ANSWER ::
x^a= y
x^a= yy^b=z
x^a= yy^b=zz^c= x
7x
∴ x = z^c = ( y^b) ^ c = y ^ bc = ( x ^a) ^bc = x^abc
So x^abc = x
∴ abc = 1 [ Equating the power of x in both sides]
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