If x ^a =y
y^ b =z
z^ c =x, then prove that abc=1
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x^a=y
(z^c)^a=y ( ∵ z^c=x)
z^ca=y
(y^b)^ca=y ( ∵ y^b=z )
y^bca=y
by comparing powers we get,
bca=1
∴abc=1 proved.
i hope that this will help u.
plzzzzzzzzzzzzzz.... mark it as the brainiest.
(z^c)^a=y ( ∵ z^c=x)
z^ca=y
(y^b)^ca=y ( ∵ y^b=z )
y^bca=y
by comparing powers we get,
bca=1
∴abc=1 proved.
i hope that this will help u.
plzzzzzzzzzzzzzz.... mark it as the brainiest.
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