If x^a=y,y^b=z,z^c=x then prove that abc=1
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x^a=y implies x= y^1/a-----(1)
y^b= z implies y = z^1/b--(2)
z ^c = y^1/a from(1)
=(z^1/b)^1/a from (2)
z ^c= z^1/ab
therefore
c =1/ab since if a^m = a ^n then m = n
abc =1
y^b= z implies y = z^1/b--(2)
z ^c = y^1/a from(1)
=(z^1/b)^1/a from (2)
z ^c= z^1/ab
therefore
c =1/ab since if a^m = a ^n then m = n
abc =1
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