Question

if x a1/÷y and when x=40,y=16. if x=10then find y​

Answer 1

Step-by-step explanation:

It given that [x \propto \frac{1} Isqrtly. x propto1/(sqrt(y))

.. IIx= |Frac\ kH|sqrt\ yH|I , where k is constant of v*pi*riati*sigma*nx = k/(sqrt(y)) where k is constant of variation

Rightarrow|Ix|times|sqrt\{y\} = kIIx * sqrt(y) = k

When x = 40, y = 15

.. Ik = 40 \times 1sqrt\{1B\} = 40 times 4 =1501Ik = 40sqrt(16) = 40 * 4 = 160

So, the equation of variation is | [x / (sqrt\{y\}) = 150IIx * sqrt(y) = 160

When x = 10,

10sqrt(y) = 160

sqrt(y) = 16

⇒ y = 16 ^ 2 = 256