if x=a4-a2-6,y=a2-2a3-2plus3a,z=8-3a-2a2-a3 then find x-(y-z)
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Answer:
13a -12 is the answer
Step-by-step explanation:
x= 4a - 2a - 6
y = 2a - 6a - 2 + 3a
z = 8 - 3a - 4a - 3a
x-(y-z) = (4a - 2a - 6) - (a2 - 6a - 2 + 3a) - (8 - 3a - 4a - 3a)
= 4a-2a-6-2a+6a+2-3a-8+3a+4a+3a
= 4a-2a-2a+6a-3a+3a+4a+3a -6+2-8 [after regrouping]
= 13a -12
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