If X=(ab)-(ab) then prove that x³+3x=ab-1/ab
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Step-by-step explanation:
Let y^3=ab, then x=y-1/y; x^3=y^3-3y^2/y+3y/y^2-1/y^3=y^3-3y+3/y-1/y^3.
3x=3y-3/y; so x^3=y^3-3x-1/y^3 and x^3+3x=y^3-1/y^3=(ab)-1/(ab)
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