If x=ab, y=bc, z=ac prove that xyz= x+y+z+2
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Answer:
xyz=x+y+z+2
ab×bc×ac =ab+bc+ac+2
(ab×bc×ac)-2 =ab +bc+ac
-2ab-2bc-2ac=ab+bc+ac
-2(ab+bc+ac)=ab+bc+ac
-2=0
therefore 0=0
and lhs =rhs
proved
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