Math, asked by idkbro1234, 4 days ago

If x=ab2 and y=a2 b2 , then LCM (x, y): HCF (x, y)​

Answers

Answered by hima63718
1
LCM = a2b2
HCF = ab2

Hope it will help you.
Answered by pulakmath007
1

SOLUTION

GIVEN

x = ab² and y = a²b²

TO DETERMINE

LCM (x, y) : HCF (x, y)

CONCEPT TO BE IMPLEMENTED

HCF :

For the given two or more numbers HCF is the greatest number that divides each of the numbers

LCM :

For the given two or more numbers LCM is the least number which is exactly divisible by each of the given numbers

EVALUATION

Here it is given that

x = ab² and y = a²b²

Now

x = ab² = a × b × b

y = a²b² = a × a × b × b

LCM (x, y) = a × a × b × b = a²b²

HCF (x, y) = a × b × b = ab²

Hence we have

LCM (x, y) : HCF (x, y)

= a²b² : ab²

= a : 1

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Learn more from Brainly :-

1. If HCF of two numbers be 40 then which of the following cannot be their LCM.

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2. The HCF and LCM of two numbers are 17 & 1666 respectively. if one of the numbers is 119 find the other

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