If x=acos^2theta and y=bsin^3theta then find dy/dx
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Answered by
0
Answer:
32b
__
27a²
Step-by-step explanation:
Given, x=acos
3
θ,y=bsin
3
θ
Therefore,
dx
dy
=
dθ
dx
dθ
dy
=
−3acos
2
θsinθ
3bsin
2
θcosθ
dx
dy
=
a
−b
tanθ
Thus
dx
2
d
2
y
=
dθ
d
(
dx
dy
)
dx
dθ
=(
a
−b
sec
2
θ)(
3acos
2
θsinθ
−1
)
=
3a
2(
4
3
×
4
3
)
2b
=
27a
2
32b
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