If x = acos¢ , y = bsin¢ then find dy/dx
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Hi !
Solution :-
dx/d¢ = d(acos¢)/d¢ = -acos¢ ______(1)
dy/d¢ = bsin¢ = +- bcos¢ _________(2)
Dividing 1 and 2 we get .
dy/dx = bcos¢/-asin¢ = -b/acot¢
_____________________________
Hope it's helpful
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