if x=acos3t ,y=bsin3t then( x÷a)power2÷3 +(y÷b)power2÷3
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Answer:
1
Step-by-step explanation:
x = aCos³t
y = bSin³t
(x/a)²/³ + (y/b)²/³
= (aCos³t/a)²/³ + (bSin³t/b)²/³
= (Cos³t)²/³ + (Sin³t)²/³ (∵ by basic exponential identity (xᵃ)ᵇ = xᵃᵇ)
= Cos²t + Sin²t
= 1.
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