Question

if x=acosø and y=bsinø then x²/a²+y²/b²​

Answer 1

Answer:

Given, x = a cos theta and y = b sin theta. Substituting for x and y ,

b²x² + a²y² - a²b² = b²a² cos² theta + a²b² sin² theta - a²b²

= a²b² (cos² theta + sin² theta) - a²b²

= a²b² . 1 - a²b² (Using the trigonometric identity cos² theta + sin² theta = 1)

= a²b² - a²b² = 0 (Proved)

Answer 2

*Question:—

if x=acosø and y=bsinø then x²/a²+y²/b²

*Answer:—

• 0 (Proved)

Step-by-step explanation:—

x = acos∅, y = bsin∅.

Substituting for x,

b²x² + a²y² - a²b² = b²a² cos²∅ - a²b² + a²y²

= b²a²(cos²∅ -1) + a²y²

= b²a²(-sin²∅) + a²y²

= -a²(b²sin²∅) + a²y²

Substitute y for b sin∅

= -a²y² + a²y²

= 0 (Proved)

$@vikramjeeth$