Question

If x=acosq and y=bsinq find dy/dx

Answer 1

Answer:

dy/dx = -b/a cotq

Explanation:

y = bsinq

dy/dq = b cosq

x = a cosq

dx/dq = -a sinq

dy/dx = (dy/dq)/ (dx/dq) = b cosq/-a sinq = -b/a cotq

i hope this will help you !!!!!