Question

if x and B are zero of the quadiaticpilynomial x^2-x-6 the find the value of x^3+B^3​

Answer 1

Step-by-step explanation:

x²-x-6=0

x²+3x-2x-6=0

x(x+3)-2(x+3)=0

(x+3)(x-2)=0

x=2

x=B=-3

x³+B³=(a+b)(a²-ab+b²)

2³+(-3)³={2-3)(2²-2(-3)+(-3)²)

=(-1)(4+6+9)

=-19.

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Answer 2

Answer:

answer attached in photo