if x and B are zero of the quadiaticpilynomial x^2-x-6 the find the value of x^3+B^3
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Step-by-step explanation:
x²-x-6=0
x²+3x-2x-6=0
x(x+3)-2(x+3)=0
(x+3)(x-2)=0
x=2
x=B=-3
x³+B³=(a+b)(a²-ab+b²)
2³+(-3)³={2-3)(2²-2(-3)+(-3)²)
=(-1)(4+6+9)
=-19.
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