Physics, asked by pillasatyanarayana74, 6 months ago

If [x] and {x} represent integral and fractional
part of x then the function defined by f(x)=
[x]+=r=11000x+r}1000 is equal to
(A) 2[x] + {x}
(B) 4x
(C) X
(D) 4[x] + 1000 {x}​

Answers

Answered by avanimudabagil12
0

Answer:

The answer is a option C

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