If [x] and {x} represent integral and fractional
part of x then the function defined by f(x)=
[x]+=r=11000x+r}1000 is equal to
(A) 2[x] + {x}
(B) 4x
(C) X
(D) 4[x] + 1000 {x}
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Answer:
The answer is a option C
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