Question

If x and y are any two positive real numbers then x > y implies
by Sy​

Answer 1

Let x and y be two positive real numbers with x < y. Using only the axioms for real numbers, show that 0 < 1/y < 1/x

I apologize for how it looks, but I'm not very good with formatting. How can I prove this?

This is what I have so far:

0 < x < y (definition of positive)

0 < 1 < y/x (division by x)

0 < 1/y < 1/x (division by y)

but it seems too simple

Plz mark on brainliest