If x and y are in direct variation and x is 40 when y is 8, find the value of x when y is 12. Also, find the constant of variation.
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It is given that the cost of apples (y) and number of apples (x) are in direct variation.
∴y∝x⇒y=kx∴y∝x⇒y=kx, where k is constant of variation
When x = 1, y = 8.
∴ 8 = k × 1
⇒ k = 8
So, the equation of variation is
y = 8x
When y = 56,
56 = 8x
⇒ x = 7
When x = 12,
y = 8 × 12 = 96
When y = 160,
160 = 8x
⇒ x = 20
Step-by-step explanation:
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