Question

If x and y are positive integers find the value of 3x-2y when x^2*y^3=256

Answer 1

Step-by-step explanation:

$256 = {x}^{2} \times {y}^{3} \\ 256 = {2}^{2} \times {4}^{3} \\ x = 2 \: \: \: \: y = 4 \\ \\ 3x - 2y \\ = 3(2) - 2(4) \\ = 6 - 8 \\ = - 2$

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