if x and y are roots of the equation 4x^2+3x+7=0, what are 1/x and 1/y
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answer:
x and y are the roots
therefore , -b/a = x
and c/ a = y
in 4x^2 + 3x + 7 = 0
a = 4 = cofficient of x^2
b = 3 = cofficient of x
c = 7 = constant number
so ,
- b/a = x = - ( -3 / 4)
c/a = y = 7/4
so
1/x = 4/-3
1/y = 4/7
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