Question

if x and y are tens and units place digits of a two digit number ,then the expression representing following condition is : sum of a two digit number and its reversible number is 88​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer: Original number= 10x + y

              Number formed on reversing the order of digits= 10y + x

              ( 10x + y ) + ( 10y + x )= 88

10x + x + 10y + y = 88

11x + 11y = 88

11( x + y ) = 88

x + y = 88/11

x + y = 8.

Step-by-step explanation:

x is tens place digit and y is ones place digit then original number will be

10x + y

and the number formed by reversing the digits at ones and tens place is

10y + x

it is given than sum of the original number and number formed by reversing the digits is equal to 88 then

( 10x + y ) + ( 10y + x )= 88

10x + x + 10y + y = 88

11x + 11y = 88

11( x + y ) = 88

x + y = 88/11

x + y = 8. It is the required equation for the given condition.