Question

if x and y are the number of possibilities that I can assume such that the unit digit of a and a cube are same and unit digit of a square and a cube are same respectively then the value of x minus y is where is a single digit number options are-:(1) 4 (2)2 (3)3 (4)5

Answer 1

Hi friend

There are totally three possibilities for this question

1,1,1

5,25,125

6,36,316

So 1,5,6 can be the possibilities

Answer 2

Hello friend,

Solution-

a is single digit hence can be from 0 to 9.

Outcomes where unit digit of a and a^3 is same = x

This can happen for,

0^3=0

1^3=1

4^3=64

5^3=125

6^3=216

9^3=729

Hence x=6

Outcomes where unit digit of a and a^2 is same = y

This can happen for,

0^2=0

1^2=1

5^2=25

6^2=36

Hence y=4

x-y=6-4=2

Hence, final answer will be x-y=2

Best luck for exams…