Question

if x and y are the two digits of the number 347 x y such that the number is completely divisible by 80 then what is the value of x + Y

Answer 1

As number is completely divisible by 80 then it must end with a zero
Now we have
347x0/80
=347x/8
=430+(3x)/8
For 3x/8 to be divisible by 8
x=2
Therefore
x+y=2+0=2
Hope this helps
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Answer 2

Answer:

The required value is 2

Step-by-step explanation:

Given : 347XY is divisible by 80

80 = 8 × 10

Since, 10 is a factor of 80 so 347XY will also be divisible by 10 and any number is divisible by 10 if and only if ones digit of the number is 0

So, only possibility for Y is Y = 0.

Now, since 8 is also a factor of 80. So, 347X0 will also be divisible by 8 and any number is divisible by 8 if its last three digits are divisible by 8.

⇒ 7X0 is divisible by 8.

So, only possibility for X is X = 2 because 720 is only multiple of 8 which starts from digit 7.

So, X + Y = 2 + 0 = 2