if x and y are two positive real number, such that 8x³+27y³=730 and 2x²y+3xy²=15,evaluate2x+3y
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Answer:
8x3 + 27y3 = 730
2x2y + 3xy2 = 15
(2x + 3y)3 = (2x)3 + (3y)3 + 3 (2x) (3y) (2x + 3y)
= 8x3 + 27y3 + 18xy (2x + 3y)
(2x + 3y)3 = 8x3 + 27y3 + 18 (2x2y + 3xy2)
(2x + 3y)2 = 730 + 18 (15)
= 730 + 270
(2x + 3y)3 = 1000
2x + 3y = 10
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