If x and y are two positive real numbers such that 9 X square + Y square=96 and X Y is=8 then find the value of 3 X + Y
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Answered by
1
we use (x+y)^2=(3x+y)^2=96+6×8=144
then 3x+y=12
then 3x+y=12
Answered by
3
(3x + y)sq. = (9x sq. + y sq.) + (6xy)
(3x + y)sq. = 96 + (6×8)
(3x + y)sq. = 96 + 48
(3x + y)sq. = 144
(3x + y) = sq. root 144
(3x + y) = 12
(3x + y)sq. = 96 + (6×8)
(3x + y)sq. = 96 + 48
(3x + y)sq. = 144
(3x + y) = sq. root 144
(3x + y) = 12
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