If X and Y are two sets such that x intersection Y has 10 elements X has 28 elements and Y has 32 elements .how many elements does X union Y have
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Answer:
X ∪ Y = 50
Step-by-step explanation:
If X and Y are two sets such that x intersection Y has 10 elements X has 28 elements and Y has 32 elements .how many elements does X union Y have
X = 28
Y = 32
X ∩ Y = 10
X only = X - X∩Y = 28 - 10 = 18
Y only = Y - X∩Y = 32 - 10 = 22
X ∪ Y = X only + Y only + X∩Y
X∪Y = 18 + 22 + 10
X ∪ Y = 50
or
X ∪ Y = X + Y - X∩ Y = 28 + 32 - 10 = 50
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