If x and y are whole numbers and 2x + y = 5, then
the total number of possible solutions of this
equation is
the answer is not infinity many please don't answer like that
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Since the question has restricted the solutions to whole number solutions, we need to substitute numbers from 0, 1, 2, .....
Let 2x + y = 5 .............. (I)
Putting x = 0 in (I) we get y= 5
Therefore, (0,5) is a solution of the equation
Similarly if x= 1 , y = 3 therefore (1,3) is a solution.
Similarly if x= 2 , y = 4 therefore (2,4) is a solution.
Now if we put x= 3 we will get y = -1 which is not a whole number.
Therefore the whole number solutions for the equation are (0,5),(1,3), (2,4)
Note that there are infinitely many REAL SOLUTIONS for a linear equation in two variables
Let 2x + y = 5 .............. (I)
Putting x = 0 in (I) we get y= 5
Therefore, (0,5) is a solution of the equation
Similarly if x= 1 , y = 3 therefore (1,3) is a solution.
Similarly if x= 2 , y = 4 therefore (2,4) is a solution.
Now if we put x= 3 we will get y = -1 which is not a whole number.
Therefore the whole number solutions for the equation are (0,5),(1,3), (2,4)
Note that there are infinitely many REAL SOLUTIONS for a linear equation in two variables
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